Exemples

Intérêts composés — Worked Examples

5 real worked examples for the Intérêts composés calculator. See how we solve common scenarios with full step-by-step math.

1

Long-term retirement growth

Scénario

A 25-year-old invests $500/month at 7% annual return, compounded monthly, until age 65 (40 years).

Entrées

Monthly contribution
$500
Annual return
7%
Compounding
monthly
Years
40

Étapes du calcul

  1. Monthly rate: 0.07 / 12 = 0.00583
  2. Number of periods: 40 × 12 = 480
  3. FV = 500 × [((1.00583)⁴⁸⁰ − 1) / 0.00583]
  4. FV = 500 × [1427.5 / 0.00583] — wait, let me redo:
  5. FV = 500 × [(1.00583)⁴⁸⁰ − 1] / 0.00583
  6. FV ≈ 500 × 2738.6
  7. FV ≈ $1,369,300

Résultat

Future value: $1,369,300 • Of which contributions: $240,000, growth: $1,129,300

2

Lump-sum investment

Scénario

A one-time $10,000 investment at 6% annual return, compounded annually, for 30 years.

Entrées

Initial
$10,000
Annual return
6%
Compounding
annually
Years
30

Étapes du calcul

  1. A = 10000 × (1.06)³⁰
  2. A = 10000 × 5.7435
  3. A ≈ $57,435

Résultat

Future value: $57,435 (5.7× growth) • Interest earned: $47,435

3

High-yield savings

Scénario

$25,000 in a savings account at 4.5% APY, compounded daily, for 5 years.

Entrées

Principal
$25,000
APY
4.5%
Compounding
daily
Years
5

Étapes du calcul

  1. Daily rate: 0.045 / 365 = 0.000123
  2. Periods: 5 × 365 = 1825
  3. A = 25000 × (1.000123)¹⁸²⁵
  4. A = 25000 × 1.2523
  5. A ≈ $31,308

Résultat

Future value: $31,308 • Interest earned: $6,308 over 5 years

4

Doubling time with Rule of 72

Scénario

How long to double $1,000 at 8% annual return?

Entrées

Principal
$1,000
Annual return
8%

Étapes du calcul

  1. Rule of 72: Years to double ≈ 72 / rate
  2. 72 / 8 = 9 years
  3. Verify with formula: A = 1000 × (1.08)⁹
  4. A = 1000 × 1.999 = $1,999 ✓

Résultat

Doubling time: 9 years. Rule of 72 is accurate for 5-12% rates. For higher rates, use 69.3 / r × ln(2) for precision.

5

Inflation erosion of purchasing power

Scénario

How much will $100,000 be worth in 20 years at 3% annual inflation?

Entrées

Today's value
$100,000
Inflation rate
3%
Years
20

Étapes du calcul

  1. Real value = 100000 / (1.03)²⁰
  2. Real value = 100000 / 1.8061
  3. Real value ≈ $55,367

Résultat

$100K today buys the same as $55,367 in 20 years. Inflation cuts purchasing power in half every ~24 years at 3%.

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